Today I will cover a simple concept question which involve 2 scenarios yet this type of question frequently appears in test & exam.
Question
Mr
Lee has a bag of sweets to distribute to his pupils.
If
he gives each pupil 8 sweets, he will have 8 sweets left.
If
he gives each pupil 6 sweets, he will have 86 sweets left. How many
pupils are there in his class? How many sweets does he has in his
bag?
Method
1
Dfference
in number of sweets per pupils is 8 - 6 = 2
Difference
in number of sweets left 86 - 8 = 78
Number
of pupils = 78 / 2 = 39
Total
number of sweets 8 x 39 + 8 = 320
( or 6 x 39 + 86 = 320 )
Method
2
Let
the number of pupils be 1 unit
Total
sweets = 8 units + 8 = 6 units + 86
8U - 6U 
86 - 8
86 - 8
2U 78
78
1U 39
39
Total
sweets = 8 x 39 + 8 = 6 x 39 + 86 = 320
Ans
: 320 sweets and 39 pupils
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